第16章波動

Consider two sinusoidal waves traveling along a string, modeled as $y_1\left(x,t\right)=0.3\text{m}\text{sin}\left(4{\text{m}}^{\mathrm{-1}}x+3{\text{s}}^{\mathrm{-1}}t\right)$ and $y_2\left(x,t\right)=0.6\text{m}\text{sin}\left(8{\text{m}}^{\mathrm{-1}}x-6{\text{s}}^{\mathrm{-1}}t\right).$ What is the height of the resultant wave formed by the interference of the two waves at the position $x=0.5\text{m}$ at time $t=0.2\text{s?}$

Consider two sinusoidal sine waves traveling along a string, modeled as $y_1\left(x,t\right)=0.3\text{m}\text{sin}\left(4{\text{m}}^{\mathrm{-1}}x+3{\text{s}}^{\mathrm{-1}}t+\frac{\pi }{3}\right)$ and $y_2\left(x,t\right)=0.6\text{m}\text{sin}\left(8{\text{m}}^{\mathrm{-1}}x-6{\text{s}}^{\mathrm{-1}}t\right).$ What is the height of the resultant wave formed by the interference of the two waves at the position $x=1.0\text{m}$ at time $t=3.0\text{s?}$

Consider two sinusoidal sine waves traveling along a string, modeled as $y_1\left(x,t\right)=0.3\text{m}\text{sin}\left(4{\text{m}}^{\mathrm{-1}}x-3{\text{s}}^{\mathrm{-1}}t\right)$ and $y_2\left(x,t\right)=0.3\text{m}\text{sin}\left(4{\text{m}}^{\mathrm{-1}}x+3{\text{s}}^{\mathrm{-1}}t\right).$ What is the wave function of the resulting wave? [Hint: Use the trig identity $\text{sin}\left(u\pm v\right)=\text{sin}u\text{cos}v\pm \text{cos}u\text{sin}v$

Two sinusoidal waves are moving through a medium in the same direction, both having amplitudes of 3.00 cm, a wavelength of 5.20 m, and a period of 6.52 s, but one has a phase shift of an angle $\varphi$. What is the phase shift if the resultant wave has an amplitude of 5.00 cm? [Hint: Use the trig identity $\text{sin}u+\text{sin}v=2\text{sin}\left(\frac{u+v}{2}\right)\text{cos}\left(\frac{u-v}{2}\right)$

Two sinusoidal waves are moving through a medium in the positive x-direction, both having amplitudes of 6.00 cm, a wavelength of 4.3 m, and a period of 6.00 s, but one has a phase shift of an angle $\varphi =0.50\text{rad}.$ What is the height of the resultant wave at a time $t=3.15\text{s}$ and a position $x=0.45\text{m}$?

Two sinusoidal waves are moving through a medium in the positive x-direction, both having amplitudes of 7.00 cm, a wave number of $k=3.00{\text{m}}^{\mathrm{-1}},$ an angular frequency of $\omega =2.50{\text{s}}^{\mathrm{-1}},$ and a period of 6.00 s, but one has a phase shift of an angle $\varphi =\frac{\pi }{12}\text{rad}.$ What is the height of the resultant wave at a time $t=2.00\text{s}$ and a position $x=0.53\text{m?}$

Consider two waves $y_1\left(x,t\right)$ and $y_2\left(x,t\right)$ that are identical except for a phase shift propagating in the same medium. (a)What is the phase shift, in radians, if the amplitude of the resulting wave is 1.75 times the amplitude of the individual waves? (b) What is the phase shift in degrees? (c) What is the phase shift as a percentage of the individual wavelength?

Two sinusoidal waves, which are identical except for a phase shift, travel along in the same direction. The wave equation of the resultant wave is $y_R\left(x,t\right)=0.70\text{m}\text{sin}(3.00{\text{m}}^{\mathrm{-1}}x-6.28{\text{s}}^{\mathrm{-1}}t+$
$\pi \text{/}16\text{rad}).$ What are the angular frequency, wave number, amplitude, and phase shift of the individual waves?

Two sinusoidal waves, which are identical except for a phase shift, travel along in the same direction. The wave equation of the resultant wave is $y_R\left(x,t\right)=0.35\text{cm}\text{sin}\left(6.28{\text{m}}^{\mathrm{-1}}x-1.57{\text{s}}^{\mathrm{-1}}t+\frac{\pi }{4}\right).$ What are the period, wavelength, amplitude, and phase shift of the individual waves?

Consider two wave functions, $y_1\left(x,t\right)=4.00\text{m}\text{sin}\left(\pi {\text{m}}^{\mathrm{-1}}x-\pi {\text{s}}^{\mathrm{-1}}t\right)$ and $y_2\left(x,t\right)=4.00\text{m}\text{sin}\left(\pi {\text{m}}^{\mathrm{-1}}x-\pi {\text{s}}^{\mathrm{-1}}t+\frac{\pi }{3}\right).$ (a) Using a spreadsheet, plot the two wave functions and the wave that results from the superposition of the two wave functions as a function of position $\left(0.00\le x\le 6.00\text{m}\right)$ for the time $t=0.00\text{s}.$ (b) What are the wavelength and amplitude of the two original waves? (c) What are the wavelength and amplitude of the resulting wave?

Consider two wave functions, $y_2\left(x,t\right)=2.00\text{m}\text{sin}\left(\frac{\pi }{2}{\text{m}}^{\mathrm{-1}}x-\frac{\pi }{3}{\text{s}}^{\mathrm{-1}}t\right)$ and $y_2\left(x,t\right)=2.00\text{m}\text{sin}\left(\frac{\pi }{2}{\text{m}}^{\mathrm{-1}}x-\frac{\pi }{3}{\text{s}}^{\mathrm{-1}}t+\frac{\pi }{6}\right).$ (a) Verify that $y_R=2A\text{cos}\left(\frac{\varphi }{2}\right)\text{sin}\left(kx-\omega t+\frac{\varphi }{2}\right)$ is the solution for the wave that results from a superposition of the two waves. Make a column for x, $y_1$, $y_2$, $y_1+y_2$, and $y_R=2A\text{cos}\left(\frac{\varphi }{2}\right)\text{sin}\left(kx-\omega t+\frac{\varphi }{2}\right).$ Plot four waves as a function of position where the range of x is from 0 to 12 m.

Consider two wave functions that differ only by a phase shift, $y_1\left(x,t\right)=A\text{cos}\left(kx-\omega t\right)$ and $y_2\left(x,t\right)=A\text{cos}\left(kx-\omega t+\varphi \right).$ Use the trigonometric identities $\text{cos}u+\text{cos}v=2\text{cos}\left(\frac{u-v}{2}\right)\text{cos}\left(\frac{u+v}{2}\right)$ and $\text{cos}\left(\text{−}\theta \right)=\text{cos}\left(\theta \right)$ to find a wave equation for the wave resulting from the superposition of the two waves. Does the resulting wave function come as a surprise to you?